Ускоренное расширение Вселенной и Тёмная Материя

Last modified by Alexey Popov on 2020/12/22 12:52

$\nabla \cdot \mathbf j = \rho_j$

$\mathbf j = G\frac{Q}{R^2}$

$\mathbf v = \sqrt{G\frac{M}{R}}$

$\mathbf v = \sqrt[3]{ G \frac{dM}{dt}}$

$\nabla \cdot \mathbf s = \rho_s$

$\mathbf s = G \frac{d^2 M}{dt^2}\frac{1}{R^2}$

$\mathbf a = \sqrt{G \frac{d^2 M}{dt^2}\frac{1}{R}}$

$\frac{\mathbf a}{R} = \sqrt{G \frac{d^2 M}{dt^2}\frac{1}{R^3}}$

$H_0^2 = \sqrt{G \frac{d^2 \rho}{dt^2}}$

$\mathbf v = \sqrt[4]{G \frac{d^2 M}{dt^2}R}$

$\frac{\mathbf v}{R} = \sqrt[4]{G \frac{d^2 M}{dt^2}\frac{1}{R^3}}$

$H_0 = \sqrt[4]{G \frac{d^2 \rho}{dt^2}}$

$\nabla \times \mathbf a = - G\rho \boldsymbol \omega$

$\nabla \cdot \mathbf v = - \frac{1}{\rho_q}\rho_{v}$

$\nabla \times \mathbf j = - \frac{1}{\rho_q}\rho_{a} \boldsymbol \omega$

$\nabla \cdot \mathbf a = - \frac{1}{\rho_q}\rho_a$

$\nabla \times \mathbf a = - \frac{1}{\rho_q}\rho_{v} \boldsymbol \omega$

$\Delta \mathbf a = - \frac{1}{\rho_q \, c^2}\rho_j \mathbf v = -\frac{1}{c^2}\mathbf s$

$\Delta (\nabla \cdot \mathbf a) = -\frac{1}{\rho_a\, c^2}\rho_s$

$F = \frac{1}{\rho\, c^2}I_{1v}I_{2v}$

$I_v = \int \rho_v \mathbf v \cdot d\mathbf S$

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Created by Alexey Popov on 2020/11/19 13:55

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