Тёмный закон всемирного тяготения

Last modified by Alexey Popov on 2020/04/09 13:06

$\nabla \cdot \mathbf a = - 4\pi G \rho$

$\nabla \cdot \mathbf s = 4\pi c^2 G \nabla^2 \rho$

$\mathbf s = \frac{d^2 \mathbf a}{dt^2}$

$\rho_g = - c^2 \nabla^2 \rho$

$\nabla \cdot \mathbf s = -4\pi G \rho_g$

$F=G\cdot \frac{m\cdot M }{r^{2}}$

$F= K_g \cdot \frac{m\cdot Q_g }{r^{2}}$

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Created by Alexey Popov on 2020/03/11 12:12