Темная материя

Last modified by Alexey Popov on 2020/08/05 09:29

$\nabla \cdot \mathbf a = \frac{1}{\rho\,c} \frac{\partial \rho_g \,r}{\partial t} + \frac{1}{\rho\,c} \rho_g \, v + \frac{1}{\rho\,c} r\frac{\partial \rho_g }{\partial t}$

$\mathbf a = \frac{1}{\rho\,c} \frac{\partial Q \mathbf r}{\partial t} \frac{1}{r^2}+ \frac{1}{\rho\,c} Q \mathbf v\frac{1}{r^2} + \frac{1}{\rho\,c} \frac{\partial Q }{\partial t}\frac{\mathbf r}{r^2}$

$\nabla \cdot \mathbf a = \frac{G}{c} \frac{\partial \rho \, r}{\partial t} + \frac{G}{c} \rho\, v + \frac{G}{\,c} \, r\frac{\partial \rho }{\partial t}$

$\mathbf a = \frac{G}{c} \frac{\partial M \mathbf r}{\partial t} \frac{1}{r^2}+ \frac{G}{c} M \mathbf v\frac{1}{r^2} + \frac{G}{c} \frac{\partial M }{\partial t}\frac{\mathbf r}{r^2}$

$\frac{\partial M}{\partial t} = \frac{v^2\, c}{G} = \frac{220000^2 * 3e8}{6.67e{-11}} = 2.17691e29 \left[\frac{kg}{s}\right]$

$\frac{\partial M}{\partial t} \frac{1}{n} = \frac{2.17691e29}{1e12} = 2.17691e17 \left[\frac{kg}{s}\right]$

$60*60*24*365 = 31\,536\,000$

$2.17691e17 * 31\,536\,000 = 6.86511e24 \left [\frac{kg}{year}\right ]$

$6.86511e24 * 1,000,000 = 6.86511e30 \left[kg\right]$

$\mathbf a = \frac{G}{c}\frac{\partial M}{\partial t}\frac{1}{R} = 2.17691e17 * 6,67e{-11} / 3e8 / 150e9 = 3.22667E-13 \left [\frac{m}{s^2}\right ]$

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Created by Alexey Popov on 2020/08/04 21:18