Темная материя 3_0

Last modified by Alexey Popov on 2021/01/18 15:05

$\Delta \mathbf a = -\frac{G}{c^2}\rho\mathbf a_n$

$\mathbf a = -\frac{G}{c^2}\frac{M\mathbf a_n}{R}$

$\Delta \nabla \cdot \mathbf a = -\frac{G}{c^2}\rho\nabla \cdot \mathbf a_n = \frac{G^2}{c^2}\rho^2$

$\mathbf a^2 = G\rho c^2$

$\Delta\mathbf a^2 = G \rho_g$

$\mathbf a^2 =G\frac{Q_g}{R}$

$\Delta \mathbf a^2 = G \rho_g$

$\rho_g = \Delta \rho c^2$

$\mathbf a = c\frac{\mathbf R}{R}\sqrt{G \frac{Q}{R}}$

$\mathbf a\, R = c\sqrt{G Q \mathbf R}$

$\mathbf v = \sqrt{c\sqrt{G Q \mathbf R}}$

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Created by Alexey Popov on 2020/12/25 11:08

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