Полная производная от квадрата вектора скорости

Last modified by Alexey Popov on 2019/03/07 10:19

$\frac{D \mathbf u^2}{Dt} = \frac{\partial \mathbf u^2}{\partial t} + \mathbf u \cdot (\nabla \mathbf u^2)$

$\mathbf {u} \cdot (\nabla \mathbf u^2 ) = \nabla \cdot (\mathbf u^2 \mathbf {u} )-\mathbf u^2 \ (\nabla \cdot \mathbf {u} )$

$\frac{D \mathbf u^2}{Dt} = \frac{\partial \mathbf u^2}{\partial t} + \nabla \cdot (\mathbf u^2 \mathbf {u} )-\mathbf u^2 \ (\nabla \cdot \mathbf {u} )$

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Created by Alexey Popov on 2019/03/07 10:17

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