Неэлектромагнитные поля

Last modified by Alexey Popov on 2019/04/26 10:14

$\mathbf E_g = -\frac{\partial \mathbf J}{\partial t} - \nabla (\mathbf J \cdot \mathbf J)- \Delta \mathbf E+\frac{1}{c_q^2}\frac{\partial^2 \mathbf E}{\partial t^2}+\mathbf J \times \mathbf B_g$

$\mathbf B_g = \nabla \times \mathbf J + \Delta \mathbf B-\frac{1}{c_q^2}\frac{\partial^2 \mathbf B}{\partial t^2}+\frac{1}{c^2}\left (\mathbf J \times \mathbf E_g \right )$

$\mathbf S_g = \mathbf E_g \times \mathbf B_g$

$\nabla \times \mathbf B_u =\square\mathbf S_g +\frac{\partial \mathbf E_u}{\partial t}$

$\mathbf J_u =\square\mathbf S_g$

$\mathbf E_s = -\frac{\partial \mathbf J_u}{\partial t} - \nabla (\mathbf J_u \cdot \mathbf J_u)- \Delta \mathbf E_u+\frac{1}{c_q^2}\frac{\partial^2 \mathbf E_u}{\partial t^2}+\mathbf J_u \times \mathbf B_s$

$\mathbf B_s = \nabla \times \mathbf J_u + \Delta \mathbf B_u-\frac{1}{c_q^2}\frac{\partial^2 \mathbf B_u}{\partial t^2}+\frac{1}{c^2}\left (\mathbf J_u \times \mathbf E_s \right )$

$\mathbf S_s = \mathbf E_s \times \mathbf B_s$

$\nabla \times \mathbf B_d =\square \mathbf S_s +\frac{\partial \mathbf E_d}{\partial t}$

Tags:

Created by Alexey Popov on 2019/04/24 09:26