Гравитационный момент импульса

Last modified by Alexey Popov on 2021/07/19 11:29

$\nabla \cdot \mathbf a = - G\rho$

$G\nabla \cdot \rho_I\boldsymbol \omega = 0$

$G(\nabla \times \rho_I\boldsymbol \omega) = \frac{\partial \mathbf a}{\partial t} + \mathbf j + G\rho\mathbf v$

$\nabla \times \mathbf a = -\frac{G}{c^2}\frac{\partial \rho_I\boldsymbol\omega}{\partial t}$

$\nabla \times (\nabla \times \mathbf a) = -\frac{G}{c^2}\frac{\partial \nabla \times \rho_I\boldsymbol\omega}{\partial t}$

$\nabla(\nabla \cdot\mathbf a) - \Delta \mathbf a = -\frac{1}{c^2}\frac{\partial^2 \mathbf a}{\partial t^2} -\frac{1}{c^2}\frac{\partial \mathbf j}{\partial t} -\frac{G}{c^2}\frac{\partial \rho\mathbf v}{\partial t}$

$-\square \mathbf a = G\nabla \rho -\frac{1}{c^2}\frac{\partial \mathbf j}{\partial t} -\frac{G}{c^2}\frac{\partial \rho\mathbf v}{\partial t}$

$G\nabla \times(\nabla \times \rho_I\boldsymbol \omega) = \frac{\partial \nabla \times\mathbf a}{\partial t} + \nabla \times\mathbf j + G\nabla \times\rho\mathbf v$

$-G\square \rho_I\boldsymbol \omega = \nabla \times\mathbf j + G\nabla \times\rho\mathbf v$

$\nabla \times\mathbf j = -G\square \rho_I\boldsymbol \omega - G\nabla \times\rho\mathbf v$

$F = \frac{c^2 }{4\pi\rho_h}\frac{m Q_g}{R^2}$

$\rho_h = m_n^3 \frac{c^3}{h^2}$

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Created by Alexey Popov on 2021/06/18 18:33